In time and work mathematics problems we are going to learn
techniques and tricks solve work and time problems. To solve time and work
problems we have to remember certain basic rules which are
Rule 1:
If a person can do a piece of work in n days (hours), then
that person’s
1 day work = 1/n
Rule 2:
If a person is n times efficient than the second person, then
work done by
First person : Second person = n : 1
And time to complete a work by
First person : Second person = 1 : n
Rule 3:
If ratio of numbers of men required to complete a work is m :
n, then the ratio of time taken by them will be n : m.
To do the solutions quickly here are some quick tricks to
solve time and work problems and formulas to do time and work easily.
Let’s take a look
Q1. A can do a piece of work in 10 days, while B can do the
same work in 6 days. B worked for 4 days. How long will A take to complete the
remaining work?
Answer: Take a careful note on this type of work and time
problem. To do this type of problems here we shall consider total times which
are given in days as total works that a person can do, i.e. here A does 10 units
of work in 10 days (1 unit/day) and B does 6 units of work in 6 days (1
unit/day).
Now we take L.H.S of 10 and 6, which will give us the total
work that can be done together. Here L.H.S of 10 and 6 is 30.
So according to the question the remaining work is done by A
alone. We know that A’s efficiency is 3.
Therefore, A will complete the remaining work in 10/3 days.
For more examples ClickHere.
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