Work and Time Problems with Solutions

Q1. Ajay can do a piece of work in 25 days and Sanjay can finish it in 20 days. They work together for 5 days and then Ajay goes away. In how many days will Sanjay finish the remaining work? Answer: As we have done in our Previous Example, we consider that Ajay does 25 units of work in 25 days and Sanjay does 20 units of work in 20 days. Since efficiency of...

Read More

Time and Work Tricks

In time and work mathematics problems we are going to learn techniques and tricks solve work and time problems. To solve time and work problems we have to remember certain basic rules which are Rule 1: If a person can do a piece of work in n days (hours), then that person’s 1 day work = 1/n Rule 2: If a person is n times efficient than the second person,...

Read More

Problems on Ages

Problems on ages come both in bank exams and SSC exams, but the frequency that is the number questions on problems on ages is not very high. There are so many formulas on age problems which definitely reduce your time in examination hall but what if you don’t remember the formula at the time of exam or you can not recognize the formula? Well, this is why I am sharing...

Read More

How to find Square Root

How to find square root of 5 digit number, square root of 4 digit number or square root of any number without calculator has now become very easy. To find square roots you need to remember certain things that will help you find square roots quickly. Let’s take a look, The tricks to find square roots in seconds you have to remember this chart. Number ...

Read More

How to find Cube Root

To find the cube root of a number you have to keep in mind certain rules and also squares & cubes of numbers, at least 2 digit number, which are necessary. Click here. Here I will show you how to find Cube roots of numbers in seconds. Step 1 Keep in mind cubes of numbers up to 9 from 0.    Chart Number Cube Last digit ...

Read More

How to solve Calendar Maths

How to solve calendar mathematics is a great fun. Here you will get the idea about how to solve calendar math problems and can help yourself  find the day of a week for both Ordinary Year and Leap Year and even find the day of the week without knowing any particular given dates. Days Gain or Loss Ordinary Year When we move forward or backward by 1 year, then...

Read More

Calendar Math Tricks

Ordinary Year A year having 365 days is called an Ordinary Year, which has (52 complete weeks + 1 Extra/Odd day) Leap Year A Leap Year has 366 days (including 29th of February) and (52 complete weeks + 2 Extra/Odd days) A leap year is divisible by 4, like 1984, 1988, 2008, 2012 etc. A century is divisible by 400, like 1600, 2000, 2400 etc. Centuries like 1700,...

Read More

HCF and LCM

Find the largest number which divide 1356, 1868 and 2764 leaving the same remainder in each case. Ans: From the Solution Methods the required number is, HCF of (1868-1356), (2764-1356) and (2764-1868) HCF of 512, 1408 and 896 So the HCF = 8*8 = 64. Since there are only two 8s in common. Find the greatest number that divides 130, 305 and 245 leaving remainders 6, 9 and...

Read More

LCM and HCF

LCM and HCF of Fractions LCM of fractions = (LCM of numerators)/(HCF of denominators) HCF of fractions = (HCF of numerators)/(LCM of denomenators) Solution Methods: Product of two numbers = HCF of the numbers * LCM of the numbers. The greatest number which divides the numbers x, y and z, leaving remainders a, b and c respectively is given by HCF of (x-a),...

Read More

Number Series

n² Series Find the missing term in the series 4, 16, 36, 64, ..., 144. Ans: This is a series of squares of consecutive even numbers. 2² = 4, 4² = 16, 6² = 36, 8² = 64, 10² = 100 (n² + 1) Series Find the missing term in the series 10, 17, ..., 37. Ans: Series pattern 3² + 1 = 10, 4² + 1 = 17, 5² + 1 = 26 (n² - 1) Series Find the missing term...

Read More

Boat and Stream Formulas

If speed of stream is ‘a’ and a boat (swimmer) takes ‘n’ times as long to row up as to row down the river, then Speed of Boat (swimmer) in still water = a*(n+1)/(n-1) A person can row at a speed of ‘x’ in still water. If stream is flowing at a speed of y, it takes time ‘T’ to row to a place and back, then Distance between two places = T*(x2 – y2) / 2x A man rows a certain distance downstream in ‘x’ hour and returns the same distance...

Read More